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Solve for a, b, c, d
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2\times \frac{1}{20}=b
Consider the first equation. Insert the known values of variables into the equation.
\frac{1}{10}=b
Multiply 2 and \frac{1}{20} to get \frac{1}{10}.
b=\frac{1}{10}
Swap sides so that all variable terms are on the left hand side.
3\times \frac{1}{10}=c
Consider the second equation. Insert the known values of variables into the equation.
\frac{3}{10}=c
Multiply 3 and \frac{1}{10} to get \frac{3}{10}.
c=\frac{3}{10}
Swap sides so that all variable terms are on the left hand side.
4\times \frac{3}{10}=d
Consider the third equation. Insert the known values of variables into the equation.
\frac{6}{5}=d
Multiply 4 and \frac{3}{10} to get \frac{6}{5}.
d=\frac{6}{5}
Swap sides so that all variable terms are on the left hand side.
a=\frac{1}{20} b=\frac{1}{10} c=\frac{3}{10} d=\frac{6}{5}
The system is now solved.