Solve for a, c
a=3
c=1
Share
Copied to clipboard
a=\frac{15}{5}
Consider the second equation. Divide both sides by 5.
a=3
Divide 15 by 5 to get 3.
2\times 3+3c=9
Consider the first equation. Insert the known values of variables into the equation.
6+3c=9
Multiply 2 and 3 to get 6.
3c=9-6
Subtract 6 from both sides.
3c=3
Subtract 6 from 9 to get 3.
c=\frac{3}{3}
Divide both sides by 3.
c=1
Divide 3 by 3 to get 1.
a=3 c=1
The system is now solved.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}