Solve {l}{2(x-3)=0}{12x-4y=18}

$$\left. \begin{array} { l } { 2 ( x - 3 ) = 0 } \\ { 12 x - 4 y = 18 } \end{array} \right.$$

Solve for x, y

$$x=3$$

$$y = \frac{9}{2} = 4\frac{1}{2} = 4.5$$

Solution Steps

Consider the first equation. Divide both sides by 2. Zero divided by any non-zero number gives zero.

$$x-3=0$$

Add 3 to both sides. Anything plus zero gives itself.

$$x=3$$

Consider the second equation. Insert the known values of variables into the equation.

$$12\times 3-4y=18$$

Multiply 12 and 3 to get 36.

$$36-4y=18$$

Subtract 36 from both sides.

$$-4y=18-36$$

Subtract 36 from 18 to get -18.

$$-4y=-18$$

Divide both sides by -4.

$$y=\frac{-18}{-4}$$

Reduce the fraction \frac{-18}{-4} to lowest terms by extracting and canceling out -2.

$$y=\frac{9}{2}$$

The system is now solved.

$$x=3 y=\frac{9}{2}$$