Solve {l}{2(x-1)=0}{-3(m+2)=1}

$$\left. \begin{array} { l } { 2 ( x - 1 ) = 0 } \\ { - 3 ( m + 2 ) = 1 } \end{array} \right.$$

Solve for x, m

$$x=1$$

$$m = -\frac{7}{3} = -2\frac{1}{3} \approx -2.333333333$$

Solution Steps

Consider the first equation. Divide both sides by 2. Zero divided by any non-zero number gives zero.

$$x-1=0$$

Add 1 to both sides. Anything plus zero gives itself.

$$x=1$$

Consider the second equation. Divide both sides by -3.

$$m+2=-\frac{1}{3}$$

Subtract 2 from both sides.

$$m=-\frac{1}{3}-2$$

Subtract 2 from -\frac{1}{3} to get -\frac{7}{3}.

$$m=-\frac{7}{3}$$

The system is now solved.

$$x=1 m=-\frac{7}{3}$$