Solve {l}{2(8+p)=22}{m+4(2m-3)=-3}

$$\left. \begin{array} { l } { 2 ( 8 + p ) = 22 } \\ { m + 4 ( 2 m - 3 ) = - 3 } \end{array} \right.$$

Solve for p, m

$$p=3$$

$$m=1$$

Solution Steps

Consider the first equation. Divide both sides by 2.

$$8+p=\frac{22}{2}$$

Divide 22 by 2 to get 11.

$$8+p=11$$

Subtract 8 from both sides.

$$p=11-8$$

Subtract 8 from 11 to get 3.

$$p=3$$

Consider the second equation. Use the distributive property to multiply 4 by 2m-3.

$$m+8m-12=-3$$

Combine m and 8m to get 9m.

$$9m-12=-3$$

Add 12 to both sides.

$$9m=-3+12$$

Add -3 and 12 to get 9.

$$9m=9$$

Divide both sides by 9.

$$m=\frac{9}{9}$$

Divide 9 by 9 to get 1.

$$m=1$$

The system is now solved.

$$p=3 m=1$$