Solve {l}{2(4-3^2)-8+sqrt[3]{125}+2^3+2}{2(-0)-8+5+8+2}

$$\left. \begin{array} { l } { 2 ( 4 - 3 ^ { 2 } ) - 8 + \sqrt[ 3 ] { 125 } + 2 ^ { 3 } + 2 } \\ { 2 ( - 0 ) - 8 + 5 + 8 + 2 } \end{array} \right.$$

Sort

$$-3,\ 7$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$sort(2\left(4-9\right)-8+\sqrt[3]{125}+2^{3}+2,2\times 0-8+5+8+2)$$

Subtract 9 from 4 to get -5.

$$sort(2\left(-5\right)-8+\sqrt[3]{125}+2^{3}+2,2\times 0-8+5+8+2)$$

Multiply 2 and -5 to get -10.

$$sort(-10-8+\sqrt[3]{125}+2^{3}+2,2\times 0-8+5+8+2)$$

Subtract 8 from -10 to get -18.

$$sort(-18+\sqrt[3]{125}+2^{3}+2,2\times 0-8+5+8+2)$$

Calculate \sqrt[3]{125} and get 5.

$$sort(-18+5+2^{3}+2,2\times 0-8+5+8+2)$$

Add -18 and 5 to get -13.

$$sort(-13+2^{3}+2,2\times 0-8+5+8+2)$$

Calculate 2 to the power of 3 and get 8.

$$sort(-13+8+2,2\times 0-8+5+8+2)$$

Add -13 and 8 to get -5.

$$sort(-5+2,2\times 0-8+5+8+2)$$

Add -5 and 2 to get -3.

$$sort(-3,2\times 0-8+5+8+2)$$

Multiply 2 and 0 to get 0.

$$sort(-3,0-8+5+8+2)$$

Subtract 8 from 0 to get -8.

$$sort(-3,-8+5+8+2)$$

Add -8 and 5 to get -3.

$$sort(-3,-3+8+2)$$

Add -3 and 8 to get 5.

$$sort(-3,5+2)$$

Add 5 and 2 to get 7.

$$sort(-3,7)$$

The list values are already in order.

$$-3,7$$

Evaluate

$$-3,\ 7$$