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sort(14,\left(3-\sqrt{6}\right)\left(3+\sqrt{6}\right))
Multiply 2 and 7 to get 14.
sort(14,3^{2}-\left(\sqrt{6}\right)^{2})
Consider \left(3-\sqrt{6}\right)\left(3+\sqrt{6}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
sort(14,9-\left(\sqrt{6}\right)^{2})
Calculate 3 to the power of 2 and get 9.
sort(14,9-6)
The square of \sqrt{6} is 6.
sort(14,3)
Subtract 6 from 9 to get 3.
14
To sort the list, start from a single element 14.
3,14
Insert 3 to the appropriate location in the new list.