Solve {l}{2*[(-1)^3-(-3/2)^2]+1/2}{[(-1)^2]^2}

$$\left. \begin{array} { l } { 2 \times [ ( - 1 ) ^ { 3 } - ( - \frac { 3 } { 2 } ) ^ { 2 } ] + \frac { 1 } { 2 } } \\ { [ ( - 1 ) ^ { 2 } ] ^ { 2 } } \end{array} \right.$$

Sort

$$-6,\ 1$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$sort(2\left(\left(-1\right)^{3}-\left(-\frac{3}{2}\right)^{2}\right)+\frac{1}{2},\left(-1\right)^{4})$$

Calculate -1 to the power of 3 and get -1.

$$sort(2\left(-1-\left(-\frac{3}{2}\right)^{2}\right)+\frac{1}{2},\left(-1\right)^{4})$$

Calculate -\frac{3}{2} to the power of 2 and get \frac{9}{4}.

$$sort(2\left(-1-\frac{9}{4}\right)+\frac{1}{2},\left(-1\right)^{4})$$

Subtract \frac{9}{4} from -1 to get -\frac{13}{4}.

$$sort(2\left(-\frac{13}{4}\right)+\frac{1}{2},\left(-1\right)^{4})$$

Multiply 2 and -\frac{13}{4} to get -\frac{13}{2}.

$$sort(-\frac{13}{2}+\frac{1}{2},\left(-1\right)^{4})$$

Add -\frac{13}{2} and \frac{1}{2} to get -6.

$$sort(-6,\left(-1\right)^{4})$$

Calculate -1 to the power of 4 and get 1.

$$sort(-6,1)$$

The list values are already in order.

$$-6,1$$

Evaluate

$$-6,\ 1$$