Solve {l}{2+y+4=22}{2x+4y+24=100}

$$\left. \begin{array} { l } { 2 + y + 4 = 22 } \\ { 2 x + 4 y + 24 = 100 } \end{array} \right.$$

Solve for y, x

$$x=6$$

$$y=16$$

Solution Steps

Consider the first equation. Add 2 and 4 to get 6.

$$6+y=22$$

Subtract 6 from both sides.

$$y=22-6$$

Subtract 6 from 22 to get 16.

$$y=16$$

Consider the second equation. Insert the known values of variables into the equation.

$$2x+4\times 16+24=100$$

Multiply 4 and 16 to get 64.

$$2x+64+24=100$$

Add 64 and 24 to get 88.

$$2x+88=100$$

Subtract 88 from both sides.

$$2x=100-88$$

Subtract 88 from 100 to get 12.

$$2x=12$$

Divide both sides by 2.

$$x=\frac{12}{2}$$

Divide 12 by 2 to get 6.

$$x=6$$

The system is now solved.

$$y=16 x=6$$