Solve {l}{2+4x-8=0}{5y+7x=8}

$$\left. \begin{array} { l } { 2 + 4 x - 8 = 0 } \\ { 5 y + 7 x = 8 } \end{array} \right.$$

Solve for x, y

$$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

$$y=-\frac{1}{2}=-0.5$$

Solution Steps

Consider the first equation. Subtract 8 from 2 to get -6.

$$-6+4x=0$$

Add 6 to both sides. Anything plus zero gives itself.

$$4x=6$$

Divide both sides by 4.

$$x=\frac{6}{4}$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$x=\frac{3}{2}$$

Consider the second equation. Insert the known values of variables into the equation.

$$5y+7\times \frac{3}{2}=8$$

Multiply 7 and \frac{3}{2} to get \frac{21}{2}.

$$5y+\frac{21}{2}=8$$

Subtract \frac{21}{2} from both sides.

$$5y=8-\frac{21}{2}$$

Subtract \frac{21}{2} from 8 to get -\frac{5}{2}.

$$5y=-\frac{5}{2}$$

Divide both sides by 5.

$$y=\frac{-\frac{5}{2}}{5}$$

Express \frac{-\frac{5}{2}}{5} as a single fraction.

$$y=\frac{-5}{2\times 5}$$

Multiply 2 and 5 to get 10.

$$y=\frac{-5}{10}$$

Reduce the fraction \frac{-5}{10} to lowest terms by extracting and canceling out 5.

$$y=-\frac{1}{2}$$

The system is now solved.

$$x=\frac{3}{2} y=-\frac{1}{2}$$