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Solve for y, j
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5y=41-2
Consider the first equation. Subtract 2 from both sides.
5y=39
Subtract 2 from 41 to get 39.
y=\frac{39}{5}
Divide both sides by 5.
-3j=6-5
Consider the second equation. Subtract 5 from both sides.
-3j=1
Subtract 5 from 6 to get 1.
j=-\frac{1}{3}
Divide both sides by -3.
y=\frac{39}{5} j=-\frac{1}{3}
The system is now solved.