Solve {l}{18-[-4+6-(-3+1)]}{-3+[+1-(+4-1)+1]}

$$\left. \begin{array} { l } { 18 - [ - 4 + 6 - ( - 3 + 1 ) ] } \\ { - 3 + [ + 1 - ( + 4 - 1 ) + 1 ] } \end{array} \right.$$

Evaluate

$$10$$

Solution Steps

Add -4 and 6 to get 2.

$$18-\left(2-\left(-3+1\right)\right)-3+1-\left(4-1\right)+1$$

Add -3 and 1 to get -2.

$$18-\left(2-\left(-2\right)\right)-3+1-\left(4-1\right)+1$$

The opposite of -2 is 2.

$$18-\left(2+2\right)-3+1-\left(4-1\right)+1$$

Add 2 and 2 to get 4.

$$18-4-3+1-\left(4-1\right)+1$$

Subtract 4 from 18 to get 14.

$$14-3+1-\left(4-1\right)+1$$

Subtract 3 from 14 to get 11.

$$11+1-\left(4-1\right)+1$$

Subtract 1 from 4 to get 3.

$$11+1-3+1$$

Subtract 3 from 1 to get -2.

$$11-2+1$$

Subtract 2 from 11 to get 9.

$$9+1$$

Add 9 and 1 to get 10.

$$10$$

Factor

$$2\times 5$$