Solve {l}{18div3-4}{16-8div4*2}{3^3-2^2}{(3+4)*6}{3*4+2}

$$\left. \begin{array} { l } { 18 \div 3 - 4 } \\ { 16 - 8 \div 4 \times 2 } \\ { 3 ^ { 3 } - 2 ^ { 2 } } \\ { ( 3 + 4 ) \times 6 } \\ { 3 \times 4 + 2 } \end{array} \right.$$

Sort

$$2,12,14,23,42$$

Solution Steps

Divide 18 by 3 to get 6.

$$sort(6-4,16-\frac{8}{4}\times 2,3^{3}-2^{2},\left(3+4\right)\times 6,3\times 4+2)$$

Subtract 4 from 6 to get 2.

$$sort(2,16-\frac{8}{4}\times 2,3^{3}-2^{2},\left(3+4\right)\times 6,3\times 4+2)$$

Divide 8 by 4 to get 2.

$$sort(2,16-2\times 2,3^{3}-2^{2},\left(3+4\right)\times 6,3\times 4+2)$$

Multiply 2 and 2 to get 4.

$$sort(2,16-4,3^{3}-2^{2},\left(3+4\right)\times 6,3\times 4+2)$$

Subtract 4 from 16 to get 12.

$$sort(2,12,3^{3}-2^{2},\left(3+4\right)\times 6,3\times 4+2)$$

Calculate 3 to the power of 3 and get 27.

$$sort(2,12,27-2^{2},\left(3+4\right)\times 6,3\times 4+2)$$

Calculate 2 to the power of 2 and get 4.

$$sort(2,12,27-4,\left(3+4\right)\times 6,3\times 4+2)$$

Subtract 4 from 27 to get 23.

$$sort(2,12,23,\left(3+4\right)\times 6,3\times 4+2)$$

Add 3 and 4 to get 7.

$$sort(2,12,23,7\times 6,3\times 4+2)$$

Multiply 7 and 6 to get 42.

$$sort(2,12,23,42,3\times 4+2)$$

Multiply 3 and 4 to get 12.

$$sort(2,12,23,42,12+2)$$

Add 12 and 2 to get 14.

$$sort(2,12,23,42,14)$$

To sort the list, start from a single element 2.

$$2$$

Insert 12 to the appropriate location in the new list.

$$2,12$$

Insert 23 to the appropriate location in the new list.

$$2,12,23$$

Insert 42 to the appropriate location in the new list.

$$2,12,23,42$$

Insert 14 to the appropriate location in the new list.

$$2,12,14,23,42$$

Evaluate

$$2,\ 12,\ 23,\ 42,\ 14$$