Solve {l}{17^2*4}{+sqrt{128}}

$$\left. \begin{array} { l } { 17 ^ { 2 } \times 4 } \\ { + \sqrt { 128 } } \end{array} \right.$$

Evaluate

$$4\left(2\sqrt{2}+289\right)\approx 1167.313708499$$

Solution Steps

Calculate 17 to the power of 2 and get 289.

$$289\times 4+\sqrt{128}$$

Multiply 289 and 4 to get 1156.

$$1156+\sqrt{128}$$

Factor 128=8^{2}\times 2. Rewrite the square root of the product \sqrt{8^{2}\times 2} as the product of square roots \sqrt{8^{2}}\sqrt{2}. Take the square root of 8^{2}.

$$1156+8\sqrt{2}$$