Solve {l}{17^2:(-17)^2}{(324)^2*(-18)^2}

$$\left. \begin{array} { l } { 17 ^ { 2 } : ( - 17 ) ^ { 2 } } \\ { ( 324 ) ^ { 2 } \cdot ( - 18 ) ^ { 2 } } \end{array} \right.$$

Sort

$$1,\ 34012224$$

Solution Steps

Calculate 17 to the power of 2 and get 289.

$$sort(\frac{289}{\left(-17\right)^{2}},324^{2}\left(-18\right)^{2})$$

Calculate -17 to the power of 2 and get 289.

$$sort(\frac{289}{289},324^{2}\left(-18\right)^{2})$$

Divide 289 by 289 to get 1.

$$sort(1,324^{2}\left(-18\right)^{2})$$

Calculate 324 to the power of 2 and get 104976.

$$sort(1,104976\left(-18\right)^{2})$$

Calculate -18 to the power of 2 and get 324.

$$sort(1,104976\times 324)$$

Multiply 104976 and 324 to get 34012224.

$$sort(1,34012224)$$

The list values are already in order.

$$1,34012224$$

Evaluate

$$1,\ 34012224$$