Solve {l}{16+8d=60}{4G-2d=12}

$$\left. \begin{array} { l } { 16 + 8 d = 60 } \\ { 4 G - 2 d = 12 } \end{array} \right.$$

Solve for d, G

$$d = \frac{11}{2} = 5\frac{1}{2} = 5.5$$

$$G = \frac{23}{4} = 5\frac{3}{4} = 5.75$$

Solution Steps

Consider the first equation. Subtract 16 from both sides.

$$8d=60-16$$

Subtract 16 from 60 to get 44.

$$8d=44$$

Divide both sides by 8.

$$d=\frac{44}{8}$$

Reduce the fraction \frac{44}{8} to lowest terms by extracting and canceling out 4.

$$d=\frac{11}{2}$$

Consider the second equation. Insert the known values of variables into the equation.

$$4G-2\times \frac{11}{2}=12$$

Multiply -2 and \frac{11}{2} to get -11.

$$4G-11=12$$

Add 11 to both sides.

$$4G=12+11$$

Add 12 and 11 to get 23.

$$4G=23$$

Divide both sides by 4.

$$G=\frac{23}{4}$$

The system is now solved.

$$d=\frac{11}{2} G=\frac{23}{4}$$