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50+60y=90y\times 150+60y
Consider the second equation. Multiply 60 and 1.5 to get 90.
50+60y=13500y+60y
Multiply 90 and 150 to get 13500.
50+60y=13560y
Combine 13500y and 60y to get 13560y.
50+60y-13560y=0
Subtract 13560y from both sides.
50-13500y=0
Combine 60y and -13560y to get -13500y.
-13500y=-50
Subtract 50 from both sides. Anything subtracted from zero gives its negation.
y=\frac{-50}{-13500}
Divide both sides by -13500.
y=\frac{1}{270}
Reduce the fraction \frac{-50}{-13500} to lowest terms by extracting and canceling out -50.
150+60\times \frac{1}{270}+30=60x
Consider the first equation. Insert the known values of variables into the equation.
150+\frac{2}{9}+30=60x
Multiply 60 and \frac{1}{270} to get \frac{2}{9}.
\frac{1352}{9}+30=60x
Add 150 and \frac{2}{9} to get \frac{1352}{9}.
\frac{1622}{9}=60x
Add \frac{1352}{9} and 30 to get \frac{1622}{9}.
60x=\frac{1622}{9}
Swap sides so that all variable terms are on the left hand side.
x=\frac{\frac{1622}{9}}{60}
Divide both sides by 60.
x=\frac{1622}{9\times 60}
Express \frac{\frac{1622}{9}}{60} as a single fraction.
x=\frac{1622}{540}
Multiply 9 and 60 to get 540.
x=\frac{811}{270}
Reduce the fraction \frac{1622}{540} to lowest terms by extracting and canceling out 2.
y=\frac{1}{270} x=\frac{811}{270}
The system is now solved.