Solve {l}{15+(-2)*(-4)*(+5)*(-6)-(-7)*(-10)}{-295}

$$\left. \begin{array} { l } { 15 + ( - 2 ) \cdot ( - 4 ) \cdot ( + 5 ) \cdot ( - 6 ) - ( - 7 ) \cdot ( - 10 ) } \\ { - 295 } \end{array} \right.$$

Evaluate

$$-590$$

Solution Steps

Multiply -2 and -4 to get 8.

$$15+8\times 5\left(-6\right)-\left(-7\left(-10\right)\right)-295$$

Multiply 8 and 5 to get 40.

$$15+40\left(-6\right)-\left(-7\left(-10\right)\right)-295$$

Multiply 40 and -6 to get -240.

$$15-240-\left(-7\left(-10\right)\right)-295$$

Subtract 240 from 15 to get -225.

$$-225-\left(-7\left(-10\right)\right)-295$$

Multiply -7 and -10 to get 70.

$$-225-70-295$$

Subtract 70 from -225 to get -295.

$$-295-295$$

Subtract 295 from -295 to get -590.

$$-590$$

Factor

$$-590$$