Solve {l}{13*3-4*1-(20-13+4)*2}{13*3-4*1-[20-(13+4)]*2}

$$\left. \begin{array} { l } { 13 \cdot 3 - 4 \cdot 1 - ( 20 - 13 + 4 ) \cdot 2 } \\ { 13 \cdot 3 - 4 \cdot 1 - [ 20 - ( 13 + 4 ) ] \cdot 2 } \end{array} \right.$$

Sort

$$13,\ 29$$

Solution Steps

Multiply 13 and 3 to get 39.

$$sort(39-4\times 1-\left(20-13+4\right)\times 2,13\times 3-4\times 1-\left(20-\left(13+4\right)\right)\times 2)$$

Multiply 4 and 1 to get 4.

$$sort(39-4-\left(20-13+4\right)\times 2,13\times 3-4\times 1-\left(20-\left(13+4\right)\right)\times 2)$$

Subtract 4 from 39 to get 35.

$$sort(35-\left(20-13+4\right)\times 2,13\times 3-4\times 1-\left(20-\left(13+4\right)\right)\times 2)$$

Subtract 13 from 20 to get 7.

$$sort(35-\left(7+4\right)\times 2,13\times 3-4\times 1-\left(20-\left(13+4\right)\right)\times 2)$$

Add 7 and 4 to get 11.

$$sort(35-11\times 2,13\times 3-4\times 1-\left(20-\left(13+4\right)\right)\times 2)$$

Multiply 11 and 2 to get 22.

$$sort(35-22,13\times 3-4\times 1-\left(20-\left(13+4\right)\right)\times 2)$$

Subtract 22 from 35 to get 13.

$$sort(13,13\times 3-4\times 1-\left(20-\left(13+4\right)\right)\times 2)$$

Multiply 13 and 3 to get 39.

$$sort(13,39-4\times 1-\left(20-\left(13+4\right)\right)\times 2)$$

Multiply 4 and 1 to get 4.

$$sort(13,39-4-\left(20-\left(13+4\right)\right)\times 2)$$

Subtract 4 from 39 to get 35.

$$sort(13,35-\left(20-\left(13+4\right)\right)\times 2)$$

Add 13 and 4 to get 17.

$$sort(13,35-\left(20-17\right)\times 2)$$

Subtract 17 from 20 to get 3.

$$sort(13,35-3\times 2)$$

Multiply 3 and 2 to get 6.

$$sort(13,35-6)$$

Subtract 6 from 35 to get 29.

$$sort(13,29)$$

The list values are already in order.

$$13,29$$

Evaluate

$$13,\ 29$$