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Solve for Q, P, M, A, T
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125Q+25Q=250
Consider the first equation. Add 25Q to both sides.
150Q=250
Combine 125Q and 25Q to get 150Q.
Q=\frac{250}{150}
Divide both sides by 150.
Q=\frac{5}{3}
Reduce the fraction \frac{250}{150} to lowest terms by extracting and canceling out 50.
P=250-12\times 5\times \frac{5}{3}
Consider the second equation. Insert the known values of variables into the equation.
P=250-60\times \frac{5}{3}
Multiply 12 and 5 to get 60.
P=250-100
Multiply 60 and \frac{5}{3} to get 100.
P=150
Subtract 100 from 250 to get 150.
M=1.25\times \frac{5}{3}
Consider the third equation. Insert the known values of variables into the equation.
M=\frac{25}{12}
Multiply 1.25 and \frac{5}{3} to get \frac{25}{12}.
A=\frac{500}{\frac{5}{3}}+125\times \frac{5}{3}
Consider the fourth equation. Insert the known values of variables into the equation.
A=500\times \frac{3}{5}+125\times \frac{5}{3}
Divide 500 by \frac{5}{3} by multiplying 500 by the reciprocal of \frac{5}{3}.
A=300+125\times \frac{5}{3}
Multiply 500 and \frac{3}{5} to get 300.
A=300+\frac{625}{3}
Multiply 125 and \frac{5}{3} to get \frac{625}{3}.
A=\frac{1525}{3}
Add 300 and \frac{625}{3} to get \frac{1525}{3}.
T=500+0.625\times \left(\frac{5}{3}\right)^{2}
Consider the fifth equation. Insert the known values of variables into the equation.
T=500+0.625\times \frac{25}{9}
Calculate \frac{5}{3} to the power of 2 and get \frac{25}{9}.
T=500+\frac{125}{72}
Multiply 0.625 and \frac{25}{9} to get \frac{125}{72}.
T=\frac{36125}{72}
Add 500 and \frac{125}{72} to get \frac{36125}{72}.
Q=\frac{5}{3} P=150 M=\frac{25}{12} A=\frac{1525}{3} T=\frac{36125}{72}
The system is now solved.