Solve {l}{120-17+78:3+(60-400:10)}{33:11-2*(28-2*21)}

$$\left. \begin{array} { l } { 120 - 17 + 78 : 3 + ( 60 - 400 : 10 ) } \\ { 33 : 11 - 2 \cdot ( 28 - 2 \cdot 21 ) } \end{array} \right.$$

Sort

$$31,149$$

Solution Steps

Subtract 17 from 120 to get 103.

$$sort(103+\frac{78}{3}+60-\frac{400}{10},\frac{33}{11}-2\left(28-2\times 21\right))$$

Divide 78 by 3 to get 26.

$$sort(103+26+60-\frac{400}{10},\frac{33}{11}-2\left(28-2\times 21\right))$$

Add 103 and 26 to get 129.

$$sort(129+60-\frac{400}{10},\frac{33}{11}-2\left(28-2\times 21\right))$$

Add 129 and 60 to get 189.

$$sort(189-\frac{400}{10},\frac{33}{11}-2\left(28-2\times 21\right))$$

Divide 400 by 10 to get 40.

$$sort(189-40,\frac{33}{11}-2\left(28-2\times 21\right))$$

Subtract 40 from 189 to get 149.

$$sort(149,\frac{33}{11}-2\left(28-2\times 21\right))$$

Divide 33 by 11 to get 3.

$$sort(149,3-2\left(28-2\times 21\right))$$

Multiply 2 and 21 to get 42.

$$sort(149,3-2\left(28-42\right))$$

Subtract 42 from 28 to get -14.

$$sort(149,3-2\left(-14\right))$$

Multiply 2 and -14 to get -28.

$$sort(149,3-\left(-28\right))$$

The opposite of -28 is 28.

$$sort(149,3+28)$$

Add 3 and 28 to get 31.

$$sort(149,31)$$

To sort the list, start from a single element 149.

$$149$$

Insert 31 to the appropriate location in the new list.

$$31,149$$

Evaluate

$$149,\ 31$$