Solve {l}{120+(-225):(-5^2)-4^2*(-5)}{3^3*(+9)+(+12)+(-2)^4}

$$\left. \begin{array} { l } { 120 + ( - 225 ) : ( - 5 ^ { 2 } ) - 4 ^ { 2 } \cdot ( - 5 ) } \\ { 3 ^ { 3 } \cdot ( + 9 ) + ( + 12 ) + ( - 2 ) ^ { 4 } } \end{array} \right.$$

Sort

$$209,\ 271$$

Solution Steps

Calculate 5 to the power of 2 and get 25.

$$sort(120+\frac{-225}{-25}-4^{2}\left(-5\right),3^{3}\times 9+12+\left(-2\right)^{4})$$

Divide -225 by -25 to get 9.

$$sort(120+9-4^{2}\left(-5\right),3^{3}\times 9+12+\left(-2\right)^{4})$$

Add 120 and 9 to get 129.

$$sort(129-4^{2}\left(-5\right),3^{3}\times 9+12+\left(-2\right)^{4})$$

Calculate 4 to the power of 2 and get 16.

$$sort(129-16\left(-5\right),3^{3}\times 9+12+\left(-2\right)^{4})$$

Multiply 16 and -5 to get -80.

$$sort(129-\left(-80\right),3^{3}\times 9+12+\left(-2\right)^{4})$$

The opposite of -80 is 80.

$$sort(129+80,3^{3}\times 9+12+\left(-2\right)^{4})$$

Add 129 and 80 to get 209.

$$sort(209,3^{3}\times 9+12+\left(-2\right)^{4})$$

Calculate 3 to the power of 3 and get 27.

$$sort(209,27\times 9+12+\left(-2\right)^{4})$$

Multiply 27 and 9 to get 243.

$$sort(209,243+12+\left(-2\right)^{4})$$

Add 243 and 12 to get 255.

$$sort(209,255+\left(-2\right)^{4})$$

Calculate -2 to the power of 4 and get 16.

$$sort(209,255+16)$$

Add 255 and 16 to get 271.

$$sort(209,271)$$

The list values are already in order.

$$209,271$$

Evaluate

$$209,\ 271$$