Solve {l}{12(16+4)=12*16+12*4}{9(8-3)=9*8-9*3}

$$\left. \begin{array} { l } { 12 ( 16 + 4 ) = 12 \times 16 + 12 \times 4 } \\ { 9 ( 8 - 3 ) = 9 \times 8 - 9 \times 3 } \end{array} \right.$$

Verify

Solution Steps

Add 16 and 4 to get 20.

$$12\times 20=12\times 16+12\times 4\text{ and }9\left(8-3\right)=9\times 8-9\times 3$$

Multiply 12 and 20 to get 240.

$$240=12\times 16+12\times 4\text{ and }9\left(8-3\right)=9\times 8-9\times 3$$

Multiply 12 and 16 to get 192. Multiply 12 and 4 to get 48.

$$240=192+48\text{ and }9\left(8-3\right)=9\times 8-9\times 3$$

Add 192 and 48 to get 240.

$$240=240\text{ and }9\left(8-3\right)=9\times 8-9\times 3$$

Compare 240 and 240.

$$\text{true}\text{ and }9\left(8-3\right)=9\times 8-9\times 3$$

Subtract 3 from 8 to get 5.

$$\text{true}\text{ and }9\times 5=9\times 8-9\times 3$$

Multiply 9 and 5 to get 45.

$$\text{true}\text{ and }45=9\times 8-9\times 3$$

Multiply 9 and 8 to get 72.

$$\text{true}\text{ and }45=72-9\times 3$$

Multiply 9 and 3 to get 27.

$$\text{true}\text{ and }45=72-27$$

Subtract 27 from 72 to get 45.

$$\text{true}\text{ and }45=45$$

Compare 45 and 45.

$$\text{true}\text{ and }\text{true}$$

The conjunction of \text{true} and \text{true} is \text{true}.

$$\text{true}$$