Solve {l}{12div4*3+2}{3+(18-2*(3+4)+1)}

$$\left. \begin{array} { l } { 12 \div 4 \times 3 + 2 } \\ { 3 + ( 18 - 2 \times ( 3 + 4 ) + 1 ) } \end{array} \right.$$

Sort

$$8,11$$

Solution Steps

Divide 12 by 4 to get 3.

$$sort(3\times 3+2,3+18-2\left(3+4\right)+1)$$

Multiply 3 and 3 to get 9.

$$sort(9+2,3+18-2\left(3+4\right)+1)$$

Add 9 and 2 to get 11.

$$sort(11,3+18-2\left(3+4\right)+1)$$

Add 3 and 4 to get 7.

$$sort(11,3+18-2\times 7+1)$$

Multiply 2 and 7 to get 14.

$$sort(11,3+18-14+1)$$

Subtract 14 from 18 to get 4.

$$sort(11,3+4+1)$$

Add 3 and 4 to get 7.

$$sort(11,7+1)$$

Add 7 and 1 to get 8.

$$sort(11,8)$$

To sort the list, start from a single element 11.

$$11$$

Insert 8 to the appropriate location in the new list.

$$8,11$$

Evaluate

$$11,\ 8$$