Solve {l}{112+334}{+5+6}{*B}

$$\left. \begin{array} { l } { 112 + 334 } \\ { + 5 + 6 } \\ { \times B } \end{array} \right.$$

Evaluate

$$6B+451$$

Solution Steps

Add 112 and 334 to get 446.

$$446+5+6B$$

Add 446 and 5 to get 451.

$$451+6B$$

Differentiate w.r.t. B

$$6$$

Steps Using Derivative Rule for Sum

Add 112 and 334 to get 446.

$$\frac{\mathrm{d}}{\mathrm{d}B}(446+5+6B)$$

Add 446 and 5 to get 451.

$$\frac{\mathrm{d}}{\mathrm{d}B}(451+6B)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$6B^{1-1}$$

Subtract 1 from 1.

$$6B^{0}$$

For any term t except 0, t^{0}=1.

$$6\times 1$$

For any term t, t\times 1=t and 1t=t.

$$6$$