Solve {l}{104=2{(x+12)}}{text{Solvefor}ytext{where}}{y=2x}

$$\left. \begin{array} { l } { 104 = 2 {(x + 12)} }\\ { \text{Solve for } y \text{ where} } \\ { y = 2 x } \end{array} \right.$$

Solve for x, y

$$y=80$$

Solution Steps

Consider the first equation. Divide both sides by 2.

$$\frac{104}{2}=x+12$$

Divide 104 by 2 to get 52.

$$52=x+12$$

Swap sides so that all variable terms are on the left hand side.

$$x+12=52$$

Subtract 12 from both sides.

$$x=52-12$$

Subtract 12 from 52 to get 40.

$$x=40$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=2\times 40$$

Multiply 2 and 40 to get 80.

$$y=80$$

The system is now solved.

$$x=40 y=80$$