Solve {l}{100-2/3*40}{100-2/341}

$$\left. \begin{array} { l } { 100 - \frac { 2 } { 3 } \times 40 } \\ { 100 - \frac { 2 } { 3 } 41 } \end{array} \right.$$

Sort

$$\frac{218}{3},\frac{220}{3}$$

Solution Steps

Express \frac{2}{3}\times 40 as a single fraction.

$$sort(100-\frac{2\times 40}{3},100-\frac{2}{3}\times 41)$$

Multiply 2 and 40 to get 80.

$$sort(100-\frac{80}{3},100-\frac{2}{3}\times 41)$$

Convert 100 to fraction \frac{300}{3}.

$$sort(\frac{300}{3}-\frac{80}{3},100-\frac{2}{3}\times 41)$$

Since \frac{300}{3} and \frac{80}{3} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{300-80}{3},100-\frac{2}{3}\times 41)$$

Subtract 80 from 300 to get 220.

$$sort(\frac{220}{3},100-\frac{2}{3}\times 41)$$

Express \frac{2}{3}\times 41 as a single fraction.

$$sort(\frac{220}{3},100-\frac{2\times 41}{3})$$

Multiply 2 and 41 to get 82.

$$sort(\frac{220}{3},100-\frac{82}{3})$$

Convert 100 to fraction \frac{300}{3}.

$$sort(\frac{220}{3},\frac{300}{3}-\frac{82}{3})$$

Since \frac{300}{3} and \frac{82}{3} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{220}{3},\frac{300-82}{3})$$

Subtract 82 from 300 to get 218.

$$sort(\frac{220}{3},\frac{218}{3})$$

To sort the list, start from a single element \frac{220}{3}.

$$\frac{220}{3}$$

Insert \frac{218}{3} to the appropriate location in the new list.

$$\frac{218}{3},\frac{220}{3}$$

Evaluate

$$\frac{220}{3},\ \frac{218}{3}$$