Solve {l}{103/4+1/2}{897/8div12}

$$\left. \begin{array} { l } { 10 \frac { 3 } { 4 } + 1 / 2 } \\ { 89 \frac { 7 } { 8 } \div 12 } \end{array} \right.$$

Sort

$$\frac{719}{96},\frac{45}{4}$$

Solution Steps

Multiply 10 and 4 to get 40.

$$sort(\frac{40+3}{4}+\frac{1}{2},\frac{\frac{89\times 8+7}{8}}{12})$$

Add 40 and 3 to get 43.

$$sort(\frac{43}{4}+\frac{1}{2},\frac{\frac{89\times 8+7}{8}}{12})$$

Least common multiple of 4 and 2 is 4. Convert \frac{43}{4} and \frac{1}{2} to fractions with denominator 4.

$$sort(\frac{43}{4}+\frac{2}{4},\frac{\frac{89\times 8+7}{8}}{12})$$

Since \frac{43}{4} and \frac{2}{4} have the same denominator, add them by adding their numerators.

$$sort(\frac{43+2}{4},\frac{\frac{89\times 8+7}{8}}{12})$$

Add 43 and 2 to get 45.

$$sort(\frac{45}{4},\frac{\frac{89\times 8+7}{8}}{12})$$

Express \frac{\frac{89\times 8+7}{8}}{12} as a single fraction.

$$sort(\frac{45}{4},\frac{89\times 8+7}{8\times 12})$$

Multiply 89 and 8 to get 712.

$$sort(\frac{45}{4},\frac{712+7}{8\times 12})$$

Add 712 and 7 to get 719.

$$sort(\frac{45}{4},\frac{719}{8\times 12})$$

Multiply 8 and 12 to get 96.

$$sort(\frac{45}{4},\frac{719}{96})$$

Least common denominator of the numbers in the list \frac{45}{4},\frac{719}{96} is 96. Convert numbers in the list to fractions with denominator 96.

$$\frac{1080}{96},\frac{719}{96}$$

To sort the list, start from a single element \frac{1080}{96}.

$$\frac{1080}{96}$$

Insert \frac{719}{96} to the appropriate location in the new list.

$$\frac{719}{96},\frac{1080}{96}$$

Replace the obtained fractions with the initial values.

$$\frac{719}{96},\frac{45}{4}$$

Evaluate

$$\frac{45}{4},\ \frac{719}{96}$$