Solve {l}{1c+11=16500}{2c+3v=40500}

$$\left. \begin{array} { l } { 1 c + 11 = 16500 } \\ { 2 c + 3 v = 40500 } \end{array} \right.$$

Solve for c, v

$$c=16489$$

$$v = \frac{7522}{3} = 2507\frac{1}{3} \approx 2507.333333333$$

Solution Steps

Consider the first equation. Subtract 11 from both sides.

$$1c=16500-11$$

Subtract 11 from 16500 to get 16489.

$$1c=16489$$

Divide both sides by 1.

$$c=16489$$

Consider the second equation. Insert the known values of variables into the equation.

$$2\times 16489+3v=40500$$

Multiply 2 and 16489 to get 32978.

$$32978+3v=40500$$

Subtract 32978 from both sides.

$$3v=40500-32978$$

Subtract 32978 from 40500 to get 7522.

$$3v=7522$$

Divide both sides by 3.

$$v=\frac{7522}{3}$$

The system is now solved.

$$c=16489 v=\frac{7522}{3}$$