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Solve for x, y
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0-9y=8
Consider the first equation. Anything times zero gives zero.
-9y=8
Anything plus zero gives itself.
y=-\frac{8}{9}
Divide both sides by -9.
8x-15\left(-\frac{8}{9}\right)=-1
Consider the second equation. Insert the known values of variables into the equation.
8x+\frac{40}{3}=-1
Multiply -15 and -\frac{8}{9} to get \frac{40}{3}.
8x=-1-\frac{40}{3}
Subtract \frac{40}{3} from both sides.
8x=-\frac{43}{3}
Subtract \frac{40}{3} from -1 to get -\frac{43}{3}.
x=\frac{-\frac{43}{3}}{8}
Divide both sides by 8.
x=\frac{-43}{3\times 8}
Express \frac{-\frac{43}{3}}{8} as a single fraction.
x=\frac{-43}{24}
Multiply 3 and 8 to get 24.
x=-\frac{43}{24}
Fraction \frac{-43}{24} can be rewritten as -\frac{43}{24} by extracting the negative sign.
x=-\frac{43}{24} y=-\frac{8}{9}
The system is now solved.