Solve for a, b, c
a=0
b=0
c=0
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b=-2a 0=4a-2b+c 0=a+b+c
Reorder the equations.
0=4a-2\left(-2\right)a+c 0=a-2a+c
Substitute -2a for b in the second and third equation.
a=-\frac{1}{8}c c=a
Solve these equations for a and c respectively.
c=-\frac{1}{8}c
Substitute -\frac{1}{8}c for a in the equation c=a.
c=0
Solve c=-\frac{1}{8}c for c.
a=-\frac{1}{8}\times 0
Substitute 0 for c in the equation a=-\frac{1}{8}c.
a=0
Calculate a from a=-\frac{1}{8}\times 0.
b=-2\times 0
Substitute 0 for a in the equation b=-2a.
b=0
Calculate b from b=-2\times 0.
a=0 b=0 c=0
The system is now solved.
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