Solve for k, b
k=1
b=-3
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b=-3
Consider the second equation. Swap sides so that all variable terms are on the left hand side.
0=3k-3
Consider the first equation. Insert the known values of variables into the equation.
3k-3=0
Swap sides so that all variable terms are on the left hand side.
3k=3
Add 3 to both sides. Anything plus zero gives itself.
k=\frac{3}{3}
Divide both sides by 3.
k=1
Divide 3 by 3 to get 1.
k=1 b=-3
The system is now solved.
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