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Solve for x, y, z
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x=3y-3z-2
Solve -x+3y-3z=2 for x.
2\left(3y-3z-2\right)-y+2z=7
Substitute 3y-3z-2 for x in the equation 2x-y+2z=7.
y=z+1 z=\frac{5}{4}y-\frac{11}{4}
Solve the second equation for y and the third equation for z.
z=\frac{5}{4}\left(z+1\right)-\frac{11}{4}
Substitute z+1 for y in the equation z=\frac{5}{4}y-\frac{11}{4}.
z=6
Solve z=\frac{5}{4}\left(z+1\right)-\frac{11}{4} for z.
y=6+1
Substitute 6 for z in the equation y=z+1.
y=7
Calculate y from y=6+1.
x=3\times 7-3\times 6-2
Substitute 7 for y and 6 for z in the equation x=3y-3z-2.
x=1
Calculate x from x=3\times 7-3\times 6-2.
x=1 y=7 z=6
The system is now solved.