Solve {l}{-x+3y-12=0}{6=2x}

$$\left. \begin{array} { l } { - x + 3 y - 12 = 0 } \\ { 6 = 2 x } \end{array} \right.$$

Solve for x, y

$$x=3$$

$$y=5$$

Solution Steps

Consider the second equation. Divide both sides by 2.

$$\frac{6}{2}=x$$

Divide 6 by 2 to get 3.

$$3=x$$

Swap sides so that all variable terms are on the left hand side.

$$x=3$$

Consider the first equation. Insert the known values of variables into the equation.

$$-3+3y-12=0$$

Subtract 12 from -3 to get -15.

$$-15+3y=0$$

Add 15 to both sides. Anything plus zero gives itself.

$$3y=15$$

Divide both sides by 3.

$$y=\frac{15}{3}$$

Divide 15 by 3 to get 5.

$$y=5$$

The system is now solved.

$$x=3 y=5$$