Solve {l}{-8-10*{[2^3+(-2)^3]:(-113)}}{-18*9+8:(-113)}

$$\left. \begin{array} { l } { - 8 - 10 \cdot \{ [ 2 ^ { 3 } + ( - 2 ) ^ { 3 } ] : ( - 113 ) \} } \\ { - 18 \cdot 9 + 8 : ( - 113 ) } \end{array} \right.$$

Evaluate

$$-\frac{19218}{113}\approx -170.07079646$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$-8-10\times \frac{8+\left(-2\right)^{3}}{-113}-18\times 9+\frac{8}{-113}$$

Calculate -2 to the power of 3 and get -8.

$$-8-10\times \frac{8-8}{-113}-18\times 9+\frac{8}{-113}$$

Subtract 8 from 8 to get 0.

$$-8-10\times \frac{0}{-113}-18\times 9+\frac{8}{-113}$$

Zero divided by any non-zero number gives zero.

$$-8-10\times 0-18\times 9+\frac{8}{-113}$$

Multiply 10 and 0 to get 0.

$$-8-0-18\times 9+\frac{8}{-113}$$

Subtract 0 from -8 to get -8.

$$-8-18\times 9+\frac{8}{-113}$$

Multiply 18 and 9 to get 162.

$$-8-162+\frac{8}{-113}$$

Subtract 162 from -8 to get -170.

$$-170+\frac{8}{-113}$$

Fraction \frac{8}{-113} can be rewritten as -\frac{8}{113} by extracting the negative sign.

$$-170-\frac{8}{113}$$

Convert -170 to fraction -\frac{19210}{113}.

$$-\frac{19210}{113}-\frac{8}{113}$$

Since -\frac{19210}{113} and \frac{8}{113} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-19210-8}{113}$$

Subtract 8 from -19210 to get -19218.

$$-\frac{19218}{113}$$

Factor

$$-\frac{19218}{113} = -170\frac{8}{113} = -170.07079646017698$$