Solve {l}{-6(3x+4)=-6(1+4x)}{n-6=-3}

$$\left. \begin{array} { l } { - 6 ( 3 x + 4 ) = - 6 ( 1 + 4 x ) } \\ { n - 6 = - 3 } \end{array} \right.$$

Solve for x, n

$$x=3$$

$$n=3$$

Solution Steps

Consider the first equation. Cancel out -6 on both sides.

$$3x+4=1+4x$$

Subtract 4x from both sides.

$$3x+4-4x=1$$

Combine 3x and -4x to get -x.

$$-x+4=1$$

Subtract 4 from both sides.

$$-x=1-4$$

Subtract 4 from 1 to get -3.

$$-x=-3$$

Divide both sides by -1.

$$x=\frac{-3}{-1}$$

Fraction \frac{-3}{-1} can be simplified to 3 by removing the negative sign from both the numerator and the denominator.

$$x=3$$

Consider the second equation. Add 6 to both sides.

$$n=-3+6$$

Add -3 and 6 to get 3.

$$n=3$$

The system is now solved.

$$x=3 n=3$$