Solve {l}{-4x+6y=4}{-y+8y=1}

$$\left. \begin{array} { l } { - 4 x + 6 y = 4 } \\ { - y + 8 y = 1 } \end{array} \right.$$

Solve for x, y

$$x=-\frac{11}{14}\approx -0.785714286$$

$$y=\frac{1}{7}\approx 0.142857143$$

Solution Steps

Consider the second equation. Combine -y and 8y to get 7y.

$$7y=1$$

Divide both sides by 7.

$$y=\frac{1}{7}$$

Consider the first equation. Insert the known values of variables into the equation.

$$-4x+6\times \frac{1}{7}=4$$

Multiply 6 and \frac{1}{7} to get \frac{6}{7}.

$$-4x+\frac{6}{7}=4$$

Subtract \frac{6}{7} from both sides.

$$-4x=4-\frac{6}{7}$$

Subtract \frac{6}{7} from 4 to get \frac{22}{7}.

$$-4x=\frac{22}{7}$$

Divide both sides by -4.

$$x=\frac{\frac{22}{7}}{-4}$$

Express \frac{\frac{22}{7}}{-4} as a single fraction.

$$x=\frac{22}{7\left(-4\right)}$$

Multiply 7 and -4 to get -28.

$$x=\frac{22}{-28}$$

Reduce the fraction \frac{22}{-28} to lowest terms by extracting and canceling out 2.

$$x=-\frac{11}{14}$$

The system is now solved.

$$x=-\frac{11}{14} y=\frac{1}{7}$$