Solve {l}{-3x+b=0}{0x+b=3}

$$\left. \begin{array} { l } { - 3 x + b = 0 } \\ { 0 x + b = 3 } \end{array} \right.$$

Solve for x, b

$$x=1$$

$$b=3$$

Solution Steps

Consider the second equation. Anything times zero gives zero.

$$0+b=3$$

Anything plus zero gives itself.

$$b=3$$

Consider the first equation. Insert the known values of variables into the equation.

$$-3x+3=0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$-3x=-3$$

Divide both sides by -3.

$$x=\frac{-3}{-3}$$

Divide -3 by -3 to get 1.

$$x=1$$

The system is now solved.

$$x=1 b=3$$