Solve {l}{-15+10+7-8=-6quad-33}{42+(-5)-(-39)+4=(42+-5)(39+4)}

$$\left. \begin{array} { l } { - 15 + 10 + 7 - 8 = - 6 \quad - 33 } \\ { 42 + ( - 5 ) - ( - 39 ) + 4 = ( 42 + - 5 ) ( 39 + 4 ) } \end{array} \right.$$

Verify

Solution Steps

Add -15 and 10 to get -5.

$$-5+7-8=-6-33\text{ and }42-5-\left(-39\right)+4=\left(42-5\right)\left(39+4\right)$$

Add -5 and 7 to get 2.

$$2-8=-6-33\text{ and }42-5-\left(-39\right)+4=\left(42-5\right)\left(39+4\right)$$

Subtract 8 from 2 to get -6.

$$-6=-6-33\text{ and }42-5-\left(-39\right)+4=\left(42-5\right)\left(39+4\right)$$

Subtract 33 from -6 to get -39.

$$-6=-39\text{ and }42-5-\left(-39\right)+4=\left(42-5\right)\left(39+4\right)$$

Compare -6 and -39.

$$\text{false}\text{ and }42-5-\left(-39\right)+4=\left(42-5\right)\left(39+4\right)$$

Subtract 5 from 42 to get 37.

$$\text{false}\text{ and }37-\left(-39\right)+4=\left(42-5\right)\left(39+4\right)$$

The opposite of -39 is 39.

$$\text{false}\text{ and }37+39+4=\left(42-5\right)\left(39+4\right)$$

Add 37 and 39 to get 76.

$$\text{false}\text{ and }76+4=\left(42-5\right)\left(39+4\right)$$

Add 76 and 4 to get 80.

$$\text{false}\text{ and }80=\left(42-5\right)\left(39+4\right)$$

Subtract 5 from 42 to get 37.

$$\text{false}\text{ and }80=37\left(39+4\right)$$

Add 39 and 4 to get 43.

$$\text{false}\text{ and }80=37\times 43$$

Multiply 37 and 43 to get 1591.

$$\text{false}\text{ and }80=1591$$

Compare 80 and 1591.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$