Solve for b, c
b = -\frac{3}{2} = -1\frac{1}{2} = -1.5
c=2
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-\frac{1}{2}+b+2=0
Consider the first equation. Insert the known values of variables into the equation.
\frac{3}{2}+b=0
Add -\frac{1}{2} and 2 to get \frac{3}{2}.
b=-\frac{3}{2}
Subtract \frac{3}{2} from both sides. Anything subtracted from zero gives its negation.
b=-\frac{3}{2} c=2
The system is now solved.
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