Solve for x, a
x=1
a=7e\approx 19.027972799
Share
Copied to clipboard
\left(1\left(1+4\right)+2\right)e^{1}=a
Consider the first equation. Insert the known values of variables into the equation.
\left(1\times 5+2\right)e^{1}=a
Add 1 and 4 to get 5.
\left(5+2\right)e^{1}=a
Multiply 1 and 5 to get 5.
7e^{1}=a
Add 5 and 2 to get 7.
7e=a
Calculate e to the power of 1 and get e.
a=7e
Swap sides so that all variable terms are on the left hand side.
x=1 a=7e
The system is now solved.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}