Solve {l}{(x+2)(x-1)=x^2-3x+4}{text{esuelvelassiguientese}}{{l}{2x^2-4x=0}{)16x^2-80=1}}

$$\left. \begin{array} { l } { ( x + 2 ) ( x - 1 ) = x ^ { 2 } - 3 x + 4 } \\ { \text { esuelve las siguientes e } } \\ { \left. \begin{array} { l } { 2 x ^ { 2 } - 4 x = 0 } \\ { ) 16 x ^ { 2 } - 80 = 1 } \end{array} \right. } \end{array} \right.$$

Solve for x

$$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+2 by x-1 and combine like terms.

$$x^{2}+x-2=x^{2}-3x+4$$

Subtract x^{2} from both sides.

$$x^{2}+x-2-x^{2}=-3x+4$$

Combine x^{2} and -x^{2} to get 0.

$$x-2=-3x+4$$

Add 3x to both sides.

$$x-2+3x=4$$

Combine x and 3x to get 4x.

$$4x-2=4$$

Add 2 to both sides.

$$4x=4+2$$

Add 4 and 2 to get 6.

$$4x=6$$

Divide both sides by 4.

$$x=\frac{6}{4}$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$x=\frac{3}{2}$$