Solve {l}{(a+2)*5=25}{(b-12)*4=10}

$$\left. \begin{array} { l } { ( a + 2 ) \times 5 = 25 } \\ { ( b - 12 ) \cdot 4 = 10 } \end{array} \right.$$

Solve for a, b

$$a=3$$

$$b = \frac{29}{2} = 14\frac{1}{2} = 14.5$$

Solution Steps

Consider the first equation. Divide both sides by 5.

$$a+2=\frac{25}{5}$$

Divide 25 by 5 to get 5.

$$a+2=5$$

Subtract 2 from both sides.

$$a=5-2$$

Subtract 2 from 5 to get 3.

$$a=3$$

Consider the second equation. Divide both sides by 4.

$$b-12=\frac{10}{4}$$

Reduce the fraction \frac{10}{4} to lowest terms by extracting and canceling out 2.

$$b-12=\frac{5}{2}$$

Add 12 to both sides.

$$b=\frac{5}{2}+12$$

Add \frac{5}{2} and 12 to get \frac{29}{2}.

$$b=\frac{29}{2}$$

The system is now solved.

$$a=3 b=\frac{29}{2}$$