Solve for x
x=-\frac{2D_{1}\left(3et-1\right)}{y}
y\neq 0
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2D_{1}=\frac{1}{2}x\times 2y+2\times 3etD_{1}
Multiply both sides of the equation by 2y, the least common multiple of y,2.
2D_{1}=xy+2\times 3etD_{1}
Multiply \frac{1}{2} and 2 to get 1.
2D_{1}=xy+6etD_{1}
Multiply 2 and 3 to get 6.
xy+6etD_{1}=2D_{1}
Swap sides so that all variable terms are on the left hand side.
xy=2D_{1}-6etD_{1}
Subtract 6etD_{1} from both sides.
yx=2D_{1}-6eD_{1}t
The equation is in standard form.
\frac{yx}{y}=\frac{2D_{1}-6eD_{1}t}{y}
Divide both sides by y.
x=\frac{2D_{1}-6eD_{1}t}{y}
Dividing by y undoes the multiplication by y.
x=\frac{2D_{1}\left(1-3et\right)}{y}
Divide 2D_{1}-6D_{1}et by y.
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