Solve {l}{(4-a)^{2}+b^{2}=r^{2}}{a^{2}+(3-b)^{2}=b^2}{a^2+b^2=r^2}

$$\left. \begin{array} { l } { ( 4 - a ) ^ { 2 } + b ^ { 2 } = r ^ { 2 } } \\ { a ^ { 2 } + ( 3 - b ) ^ { 2 } = b ^ { 2 } } \\ { a ^ { 2 } + b ^ { 2 } = r ^ { 2 } } \end{array} \right.$$

Solve for a, b, r

$$r=-\frac{\sqrt{313}}{6}\approx -2.948634335\text{, }a=2\text{, }b=\frac{13}{6}\approx 2.166666667$$

$$r=\frac{\sqrt{313}}{6}\approx 2.948634335\text{, }a=2\text{, }b=\frac{13}{6}\approx 2.166666667$$