Solve {l}{(3^2+45^1+4+16)(5+10)=0}{5^3+149^2+605+200=0}

$$\left. \begin{array} { l } { ( 3 ^ { 2 } + 45 ^ { 1 } + 4 + 16 ) ( 5 + 10 ) = 0 } \\ { 5 ^ { 3 } + 149 ^ { 2 } + 605 + 200 = 0 } \end{array} \right.$$

Verify

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\left(9+45^{1}+4+16\right)\left(5+10\right)=0\text{ and }5^{3}+149^{2}+605+200=0$$

Calculate 45 to the power of 1 and get 45.

$$\left(9+45+4+16\right)\left(5+10\right)=0\text{ and }5^{3}+149^{2}+605+200=0$$

Add 9 and 45 to get 54.

$$\left(54+4+16\right)\left(5+10\right)=0\text{ and }5^{3}+149^{2}+605+200=0$$

Add 54 and 4 to get 58.

$$\left(58+16\right)\left(5+10\right)=0\text{ and }5^{3}+149^{2}+605+200=0$$

Add 58 and 16 to get 74.

$$74\left(5+10\right)=0\text{ and }5^{3}+149^{2}+605+200=0$$

Add 5 and 10 to get 15.

$$74\times 15=0\text{ and }5^{3}+149^{2}+605+200=0$$

Multiply 74 and 15 to get 1110.

$$1110=0\text{ and }5^{3}+149^{2}+605+200=0$$

Compare 1110 and 0.

$$\text{false}\text{ and }5^{3}+149^{2}+605+200=0$$

Calculate 5 to the power of 3 and get 125.

$$\text{false}\text{ and }125+149^{2}+605+200=0$$

Calculate 149 to the power of 2 and get 22201.

$$\text{false}\text{ and }125+22201+605+200=0$$

Add 125 and 22201 to get 22326.

$$\text{false}\text{ and }22326+605+200=0$$

Add 22326 and 605 to get 22931.

$$\text{false}\text{ and }22931+200=0$$

Add 22931 and 200 to get 23131.

$$\text{false}\text{ and }23131=0$$

Compare 23131 and 0.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$