Solve {l}{(250+(57,5*20)+71*40+83*12}{+94,5*6):88}

$$\left. \begin{array} { l } { ( 250 + ( 57,5 \cdot 20 ) + 71 \cdot 40 + 83 \cdot 12 } \\ { + 94,5 \cdot 6 ) : 88 } \end{array} \right.$$

Evaluate

$$\frac{5803}{88}\approx 65,943181818$$

Solution Steps

Multiply 71 and 40 to get 2840. Multiply 83 and 12 to get 996.

$$\frac{250+57,5\times 20+2840+996+94,5\times 6}{88}$$

Multiply 57,5 and 20 to get 1150.

$$\frac{250+1150+2840+996+94,5\times 6}{88}$$

Add 250 and 1150 to get 1400.

$$\frac{1400+2840+996+94,5\times 6}{88}$$

Add 1400 and 2840 to get 4240.

$$\frac{4240+996+94,5\times 6}{88}$$

Add 4240 and 996 to get 5236.

$$\frac{5236+94,5\times 6}{88}$$

Multiply 94,5 and 6 to get 567.

$$\frac{5236+567}{88}$$

Add 5236 and 567 to get 5803.

$$\frac{5803}{88}$$

Factor

$$\frac{7 \cdot 829}{11 \cdot 2 ^ {3}} = 65\frac{83}{88} = 65.94318181818181$$