Solve {l}{(21-3)*(7+4)}{21-3*7+4}{(14div2)*3+4}{3*7-14+4}

$$\left. \begin{array} { l } { ( 21 - 3 ) \times ( 7 + 4 ) } \\ { 21 - 3 \times 7 + 4 } \\ { ( 14 \div 2 ) \times 3 + 4 } \\ { 3 \times 7 - 14 + 4 } \end{array} \right.$$

Sort

$$4,11,25,198$$

Solution Steps

Subtract 3 from 21 to get 18.

$$sort(18\left(7+4\right),21-3\times 7+4,\frac{14}{2}\times 3+4,3\times 7-14+4)$$

Add 7 and 4 to get 11.

$$sort(18\times 11,21-3\times 7+4,\frac{14}{2}\times 3+4,3\times 7-14+4)$$

Multiply 18 and 11 to get 198.

$$sort(198,21-3\times 7+4,\frac{14}{2}\times 3+4,3\times 7-14+4)$$

Multiply 3 and 7 to get 21.

$$sort(198,21-21+4,\frac{14}{2}\times 3+4,3\times 7-14+4)$$

Subtract 21 from 21 to get 0.

$$sort(198,0+4,\frac{14}{2}\times 3+4,3\times 7-14+4)$$

Add 0 and 4 to get 4.

$$sort(198,4,\frac{14}{2}\times 3+4,3\times 7-14+4)$$

Divide 14 by 2 to get 7.

$$sort(198,4,7\times 3+4,3\times 7-14+4)$$

Multiply 7 and 3 to get 21.

$$sort(198,4,21+4,3\times 7-14+4)$$

Add 21 and 4 to get 25.

$$sort(198,4,25,3\times 7-14+4)$$

Multiply 3 and 7 to get 21.

$$sort(198,4,25,21-14+4)$$

Subtract 14 from 21 to get 7.

$$sort(198,4,25,7+4)$$

Add 7 and 4 to get 11.

$$sort(198,4,25,11)$$

To sort the list, start from a single element 198.

$$198$$

Insert 4 to the appropriate location in the new list.

$$4,198$$

Insert 25 to the appropriate location in the new list.

$$4,25,198$$

Insert 11 to the appropriate location in the new list.

$$4,11,25,198$$

Evaluate

$$198,\ 4,\ 25,\ 11$$