Solve {l}{(1)^15+(-1)^307-(-1)^0-(-2)^5}{11+(-1)-(+1)-(-32)}

$$\left. \begin{array} { l } { ( 1 ) ^ { 15 } + ( - 1 ) ^ { 307 } - ( - 1 ) ^ { 0 } - ( - 2 ) ^ { 5 } } \\ { 11 + ( - 1 ) - ( + 1 ) - ( - 32 ) } \end{array} \right.$$

Sort

$$31,\ 41$$

Solution Steps

Calculate 1 to the power of 15 and get 1.

$$sort(1+\left(-1\right)^{307}-\left(-1\right)^{0}-\left(-2\right)^{5},11-1-1-\left(-32\right))$$

Calculate -1 to the power of 307 and get -1.

$$sort(1-1-\left(-1\right)^{0}-\left(-2\right)^{5},11-1-1-\left(-32\right))$$

Subtract 1 from 1 to get 0.

$$sort(0-\left(-1\right)^{0}-\left(-2\right)^{5},11-1-1-\left(-32\right))$$

Calculate -1 to the power of 0 and get 1.

$$sort(0-1-\left(-2\right)^{5},11-1-1-\left(-32\right))$$

Subtract 1 from 0 to get -1.

$$sort(-1-\left(-2\right)^{5},11-1-1-\left(-32\right))$$

Calculate -2 to the power of 5 and get -32.

$$sort(-1-\left(-32\right),11-1-1-\left(-32\right))$$

The opposite of -32 is 32.

$$sort(-1+32,11-1-1-\left(-32\right))$$

Add -1 and 32 to get 31.

$$sort(31,11-1-1-\left(-32\right))$$

Subtract 1 from 11 to get 10.

$$sort(31,10-1-\left(-32\right))$$

Subtract 1 from 10 to get 9.

$$sort(31,9-\left(-32\right))$$

The opposite of -32 is 32.

$$sort(31,9+32)$$

Add 9 and 32 to get 41.

$$sort(31,41)$$

The list values are already in order.

$$31,41$$

Evaluate

$$31,\ 41$$