Solve {l}{(1+4+3)-(8+2)+(11+6):17=151}{18*6:27-[26-(81:9*2:3+3*6)]=[2]}

$$\left. \begin{array} { l } { ( 1 + 4 + 3 ) - ( 8 + 2 ) + ( 11 + 6 ) : 17 = 151 } \\ { 18 \cdot 6 : 27 - [ 26 - ( 81 : 9 \cdot 2 : 3 + 3 \cdot 6 ) ] = [ 2 ] } \end{array} \right.$$

Verify

Solution Steps

Add 1 and 4 to get 5.

$$5+3-\left(8+2\right)+\frac{11+6}{17}=151\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Add 5 and 3 to get 8.

$$8-\left(8+2\right)+\frac{11+6}{17}=151\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Add 8 and 2 to get 10.

$$8-10+\frac{11+6}{17}=151\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Subtract 10 from 8 to get -2.

$$-2+\frac{11+6}{17}=151\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Add 11 and 6 to get 17.

$$-2+\frac{17}{17}=151\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Divide 17 by 17 to get 1.

$$-2+1=151\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Add -2 and 1 to get -1.

$$-1=151\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Compare -1 and 151.

$$\text{false}\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Multiply 18 and 6 to get 108.

$$\text{false}\text{ and }\frac{108}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Divide 108 by 27 to get 4.

$$\text{false}\text{ and }4-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Divide 81 by 9 to get 9.

$$\text{false}\text{ and }4-\left(26-\left(\frac{9\times 2}{3}+3\times 6\right)\right)=2$$

Multiply 9 and 2 to get 18.

$$\text{false}\text{ and }4-\left(26-\left(\frac{18}{3}+3\times 6\right)\right)=2$$

Divide 18 by 3 to get 6.

$$\text{false}\text{ and }4-\left(26-\left(6+3\times 6\right)\right)=2$$

Multiply 3 and 6 to get 18.

$$\text{false}\text{ and }4-\left(26-\left(6+18\right)\right)=2$$

Add 6 and 18 to get 24.

$$\text{false}\text{ and }4-\left(26-24\right)=2$$

Subtract 24 from 26 to get 2.

$$\text{false}\text{ and }4-2=2$$

Subtract 2 from 4 to get 2.

$$\text{false}\text{ and }2=2$$

Compare 2 and 2.

$$\text{false}\text{ and }\text{true}$$

The conjunction of \text{false} and \text{true} is \text{false}.

$$\text{false}$$